Making an array of char in C

Question

I am new to C,

So I tried to make a program assigning grades according to marks of students. I need to make a char array with the first slot referring to the first student .. etc

The initialization was simple

char grade[n];

Where n is the number of students

to assign values I made a condition comparing the marks in a loop and if the condition is fulfilled this kind of statement is executed :

grade[i] == 'B';

To call the value at the end I used this :

printf("%c", &grade[i]);

Where "i" is the displaying loop control variable.

At the end, strange symbols were displayed. What is the right way to create an array of chars and calling individual "slots" ?

Answer 1

Change this

printf("%c", &grade[i]);

to

printf("%c", grade[i]);

And it should work as you expect.

Answer 2

You print pointer address, don't use & in print.

Answer 3

Just use printf("%c", grade[i]) without the "&" address-of operator. You want to print the character at index i, not the address of that character.