On Linux i386, the int $0x80
syscall ABI makes it easy to perform syscalls without having a valid userspace stack. The vdso/vsyscall interface, on the other hand, requires access to a stack. How do other Linux ports fare in this regard, especially x86_64? Do they have ways to make syscalls without a stack? Is there a reference on the available syscall methods for each arch?
Making syscalls on Linux without a stack
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In general: no idea. Even on i386, if there is a 6th argument, it must be passed on the stack (e.g. for
mmap
).For x86_64 specifically: put the syscall number in
%rax
(beware: the syscall numbers are allocated completely differently to the 32-bit ones), up to 6 arguments in%rdi
,%rsi
,%rdx
,%r10
,%r8
and%r9
(which is almost, but not quite, the same as the usual ABI for parameter passing in registers - note use of%r10
instead of%rcx
), and use thesyscall
instruction. The result is returned in%rax
, and%rcx
and%r11
are clobbered.x86_64 ABI information can be found at http://www.x86-64.org/documentation/abi.pdf; the Linux ABI is documented in the appendix. (And if looking around elsewhere for x86_64 ABI info, be aware that 64-bit Windows uses its own different ABI.)
I don't believe there is any requirement on the user stack frame for
syscall
to work properly. In the case of being interrupted by a signal, a sane stack is obviously required for the handler; but the following experiment, which uses an alternate signal stack and deliberately trashes%rsp
around thesyscall
, works fine for me: