LPC_CAN1->TDA1 = *(uint32_t *) &msg->data[0]; // Write first 4 data bytes
please tell me why this *(uint32_t ) is used and what is the purpose of this "" before and after the uint32_t
Meaning of *((uint32_t*)&..) in C
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Objective of this code is to copy first 4 bytes present at
msg->data[0]toLPC_CAN1->TDA1.&msg->data[0]gives the address of msg->data[0].(uint32_t *) &msg->data[0]casts that address to be an address pointing to a 32-bit unsigned integer.*(uint32_t *) &msg->data[0]reads uint32_t value (4-byte unsigned integer) from the address.Hope that makes sense.