Need to convert decimal to base 32, whats wrong ? base 32 = 0-9 A-V

Question

this is my code in c, need to convert from from decimal to base 32 .Getting strange symbols as output.

 #include <stdio.h>
        char * f(unsigned int num){
            static  char base[3];
            unsigned int mask=1,base32=0;
            int i,j;

            for (j=0;j<3;j++)
            for (i=0;i<5;num<<1,mask<<1){
                if (mask&num){
                    base32 = mask|base32;
                    base32<<1;
                }
                if (base32<9)   
                    base[j]=base32+'0';
                else    
                    base[j]=(char)(64+base32-9);
            }
        }

base 32 = 0-9 A-V

 int main()
                {
                    unsigned int num =100;

                    printf("%s\n",f(num));

                    return 1;
                }
            should get 34.

Answer 1

You shift both mask and num in your loop. This means you're always checking for the same bit, just moved around. Only shift one of the values, the mask.

Also you're skipping the number 9 with your comparison.

Using a debugger you can easily see what's happening and how it is going wrong.