I am new to php, and would like to pass a drop down menu value to another php file. Below is the code I have pieced together so far.
Drop down php (Lists all files in a directory, although i'd like to omit the folders and the "." & ".."):
<?php
$currentdir = 'data/';
$dir = opendir($currentdir);
echo 'Files are as follows:<br>';
echo '<form action="SelectedDate.php" method="POST">';
echo '<select name="selectedfile" onchange="this.form.submit()">';
while($file = readdir($dir))
{
echo '<option value="'.$file.'">'.$file.'</option>';
}
echo '</select>';
echo '</form>';
closedir($dir);
?>
Table generating php, which is where i'd like to pass the file name too so it can pull up the selected csv file,formatted to table. :
<?php
$var=$_REQUEST['selectedfile'];
$row = 1;
if (($handle = fopen('"data/"'$var'"', "r")) !== FALSE) {
echo '<head>';
echo '<script src="js/sorttable.js"></script>';
echo '</head>';
echo '<table class="sortable" border="1">';
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
$num = count($data);
if ($row == 1) {
echo '<thead><tr>';
}else{
echo '<tr>';
}
for ($c=0; $c < $num; $c++) {
//echo $data[$c] . "<br />\n";
if(empty($data[$c])) {
$value = " ";
}else{
$value = $data[$c];
}
if ($row == 1) {
echo '<th>'.$value.'</th>';
}else{
echo '<td>'.$value.'</td>';
}
}
if ($row == 1) {
echo '</tr></thead><tbody>';
}else{
echo '</tr>';
}
$row++;
}
echo '</tbody></table>';
fclose($handle);
}
?>
I cant seem to get the drop down value to pass into the fopen() function...
Any help and critiquing would be great!
For readability I would prefer $_POST instead of $_REQUEST, besides that you have an error:
======
Updated answer:
Make sure your files are both saved with an .php extension. Besides that, add the following lines of code to the top of your second file:
As a finishing try, use this code in the if