Perfect Number Check

Question

So the idea behind my code is to create a program that uses functions to check and print all perfect numbers between 1 and 1000. I've come up with this, but the issue is that nothing prints. It builds successfully, runs, and exits.

I've gone through my code 3-4 times and I can't find the gap in logic, so I'm thinking its a variable definition issue, something to do with how in-scope certain functions are. Would anyone have any input for why my program is failing to recognize a perfect number, and then print it?

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

/*
 * 
 */

void perfectNumCheck(int num);
void perfectNumPrint (int perfectNum);

int main(void) {

    int i;
    for (i = 1; 1 <= 1000; i++)
        perfectNumCheck(i);

}

void perfectNumCheck(int num) {

    int i;
    int temp = 0;

    for (i = 0; i < num; i++) {
        if (num % i == 0)
            temp += i;
    }

    if (temp == num)
        perfectNumPrint(num);

}

void perfectNumPrint(int perfectNum) {

    int i;
    for (i = 0; i < perfectNum; i++) 
        if (perfectNum % i == 0) 
            printf ("%d, ", i);

    printf("are factors of the perfect number %d.\n", perfectNum);

}

Answer 1

You have a typo here:

for (i = 1; 1 <= 1000; i++)
    perfectNumCheck(i);

Should be

for (i = 1; i <= 1000; i++)
    perfectNumCheck(i);

Also, you're dividing by zero. Change all your i = 0 in your for loops to i = 1

Answer 2

Perfect Number Test : If the sum of all factors are equals to number itself.

    public static bool IsItPerfectNumber(int input)
    {
        bool IsPerfectNumber = false;
        //Validation and Find all Factore 
        List<int> myList = FindFactors(input);            
        //Sum if factor
       int sumOfFactor = SumFactor(myList);

        //Check Is Perfact Number
        if (sumOfFactor == input)    
        {
            IsPerfectNumber = true;
        }
        return IsPerfectNumber;
    }

    public static List<int> FindFactors(int input)
    {
        List<int> myList = new List<int>();

        for (int j = 1; j < input; j++)
        {
            if (input % j == 0)                  {
                myList.Add(j); 
            }
        }
        return myList;
    }

    public static int SumFactor(List<int> myList)
    {
        return myList.Sum();
    }

Answer 3

Try this:

boolean perfectNum(int currentNum) {

    int i, sum = 0;
    for (i = 1; i < currentNum; i++) 
        if (perfectNum % i == 0) 
             sum += i;

    if(sum == currentNum) return ture;
    return false;

}

Answer 4

boolean perfectNum(int currentNum) {

    int i, sum = 0;
    for (i = 1; i < currentNum; i++) 
        if (perfectNum % i == 0) 
            sum += i;

    if(sum == currentNum) return ture;
    return false;
}