PHP date_format() expects parameter 1 to be DateTimeInterface

Question

I want to convert the string to date time, but it's not working

<?php  
$date = date_create_from_format('d_m_Y_H_i_s', '29_11_2016_5_0_15');
echo date_format($date, 'Y-m-d');

return

Warning: date_format() expects parameter 1 to be DateTimeInterface, boolean given ...

what is the solution ??

Answer 1

date_create_from_format() returns false when it fails, or a new DateTime instance when it succeeds.

Yours is failing because minutes are two-digits, not single-digits. Using 29_11_2016_5_0_15 as a timestring would yield the following error

A two digit minute could not be found

So simply, you'll need to use 29_11_2016_5_00_15 as the timestring instead, like this

// Try to create the datetime instance
if ($date = date_create_from_format('d_m_Y_H_i_s', '29_11_2016_5_00_15')) {
    echo date_format($date, 'Y-m-d');
} else {
    // It failed! Errors found, let's figure out what!
    echo "<pre>";
    print_r(date_get_last_errors());
    echo "</pre>";
}

The output from the above snippet would be 2016-11-29, live demo: https://3v4l.org/6om9g

Using date_get_last_errors() you'll be able to get the errors given in your DateTime instance.

Answer 2

You must use minutes with two chars, in your code is just one where shoud with leading 0.

so just pad it with leading 0.

<?php
$string = '29_11_2016_5_0_15';
$array = explode('_', $string);
$array[4] = str_pad($array[4], 2, 0, STR_PAD_LEFT);
$string = implode('_', $array);
$date = date_create_from_format('d_m_Y_H_i_s', $string);
echo date_format($date, 'Y-m-d');

Answer 3

I format date:
echo date("d/m/Y  H:i:s a", strtotime($row['timestamp']));