PHP get the basename(__DIR__) of the parent and not the directory of the included file if used inside an include

Question

My structure is as follows

public_html/includes/ contains

includeMe.php

the php inside includeMe.php is

<?php echo basename(__DIR__); ?>

public_html/stuff/ contains

myPage.php

the php inside myPage.php is

<?php include '../includes/includeMe.php'; ?>

The output with this code when I visit stuff/myPage.php is

includes

when I want the output to be

stuff

since this is the parent of where its being included from.

I know this is the correct behaviour for the code i've used so my question is, what can I echo within includeMe.php so that the result when called from the include in myPage.php is stuff without the need to move the echo to the myPage.php itself?

Answer 1

I tried a few things that worked, even with URL parameters:

//includeMe.php

echo $_SERVER['REQUEST_URI'];                    // /stuff/myPage.php?test=test

echo basename(__DIR__);                          // includes
echo basename(dirname($_SERVER['REQUEST_URI'])); // stuff
echo basename(dirname($_SERVER['SCRIPT_NAME'])); // stuff
echo basename(dirname($_SERVER['PHP_SELF']));    // stuff

I think it is noteworthy that this will only work with web request, not on CLI.