php implode multidimensional array

Question

I have an array, which started off as an empty array with

$filearray = array(array(array()));

I know how to do it if there were tag IDs set, but I seem to be struggling where I've built on it.

while (($file = readdir($dir)) !== false)
{
    //echo $file ;

    //gets the file date, string needed decoding otherwise throws error. Thanks to stackoverflow!

    $date = @filemtime($file);
    $date = date("F d Y H:i:s.", filemtime(utf8_decode("/home/a1742406/public_html/files/$file")));
    //echo $date. "<br />";

    $size = filesize("/home/a1742406/public_html/files/$file") . ' bytes';

    $filearray = array($file, $date, $size);

    print "<pre>";
    $data = implode(" ", $filearray);
    echo $data;
    //print_r($filearray);
    print "</pre>";
}

My filearray has 3 parts, file, date and size, but I want to print them separately so i can have spacing between them and put them into a table or list, but I can't seem to figure how to separate them to do it, as the above prints it all in one row. Any help would be greatly appreciated to point me in the right direction!

Thanks.

Answer 1

If you plan on printing them inside the <pre> pre formatted tags, then you could just use \n:

print "<pre>";
$data = implode(" ", $filearray);
echo $data . "\n"; // <-- new line, or if you want `\n\n`, whatever how much space you want between lines
print "</pre>";

If you also want file, date, and size in each separate lines, then you could just glue them with a newline:

print "<pre>";
$data = implode("\n", $filearray);
echo $data . "\n\n";
print "</pre>";

If you plan on presenting them on a table, then just build up the markup like you normally would do:

echo '<table cellpadding="10">';
echo '
    <tr>
        <th>File</th>
        <th>Date</th>
        <th>Size</th>
    </tr>
';

while (($file = readdir($dir)) !== false)
{
    // other codes inside

    echo '<tr>';
        echo "<td>$file</td>";
        echo "<td>$date</td>";
        echo "<td>$size</td>";
    echo '</tr>';

}
echo '</table>';

Answer 2

Try it:

$data = implode(" ", $filearray)."<br/>";

Answer 3

Since the data that you refer to are in an array, you may easily display the three items separately by using iteration and some <BR> and/or newline characters as follows for a simple list:

<?php

$file = 'filename';
$date = 'thedate';
$size = 'thesize';

$arr = array('file' => $file, 
                   'date' => $date, 
                   'size' => $size);

foreach ($arr as $key => $value) {    
    echo "$key: $value<BR>\n<BR>\n";
}

//Output:

file: filename

date: thedate

size: thesize

If you wish to have the data in a table, you might wrap the data in <tr><td> tags instead, as follows:

<?php

echo "<table>\n";
foreach ($arr as $key => $value) {    
    echo "<tr><td> $key: </td><td> $value </td></tr>\n";
}
echo "</table>\n";

Do you have any need for $filearray beyond what it does in the code you show? If not you could eliminate the $filearray and use the three variables directly by joining them with newline characters with implode() and assign the result to a variable, having the code display its value. Alternatively, you could wrap each variable in <tr><td> tags and eliminate the need to use implode().