PIC24HJ XC16 Linker Script Interrupt Vector Table

Question

I am working on a bootloader for a PIC24HJ series MCU.

While going through the linker script I noticed something, tried a google search, searched documentation, GCC linker documentation, I'm out of ideas. Anyway, going through this tutorial, step 13 has the following:

.application_ivt __APP_IVT_BASE :
{
SHORT(ABSOLUTE(__reset)); SHORT(0x04); SHORT((ABSOLUTE(__reset) >> 16) & 0x7F); SHORT(0);

SHORT(DEFINED(__OscillatorFail) ? ABSOLUTE(__OscillatorFail) : ABSOLUTE(__DefaultInterrupt)); SHORT(0x04); 
SHORT(DEFINED(__OscillatorFail) ? (ABSOLUTE(__OscillatorFail) >> 16) & 0x7F : (ABSOLUTE(__DefaultInterrupt) >> 16) & 0x7F); SHORT(0);

SHORT(DEFINED(__AddressError) ? ABSOLUTE(__AddressError) : ABSOLUTE(__DefaultInterrupt)); SHORT(0x04); 
SHORT(DEFINED(__AddressError) ? (ABSOLUTE(__AddressError) >> 16) & 0x7F : (ABSOLUTE(__DefaultInterrupt) >> 16) & 0x7F); SHORT(0);

SHORT(DEFINED(__NVMError    ) ? ABSOLUTE(__NVMError) : ABSOLUTE(__DefaultInterrupt)); SHORT(0x04); 
SHORT(DEFINED(__NVMError    ) ? (ABSOLUTE(__NVMError) >> 16) & 0x7F : (ABSOLUTE(__DefaultInterrupt) >> 16) & 0x7F); SHORT(0);

...

The question is about SHORT(0x04) (then SHORT(0x00)) after every interrupt address. This is also the case in the default linker script file. I understand taking the lower 16 bits of the address, then the upper 8 (or rather 7) bits in the next location, but why are there the 0x04 and the 0x00 staggered in there?

Thanks.