Python argument matching for f(a, *b)

Question

def f(a,*b):
    print(a,b)

for the function f defined as above, if I call f(1, *(2,3)) it prints 1, (2,3) as expected.

However calling f(a=1, *(2,3)) causes an error: TypeError: f() got multiple values for argument 'a'

Any positional argument can also be supplied as an explicit keyword argument. There should be only one interpretation for f(a=1, *(2,3)) without ambiguity.

Answer 1

def f(a,*b):
    print(a,b)
f(1,*(2,3))
f(1,2,3)

consider the example above both will call the same function in the same way now if you specify a =1

f(a=1,2,3)
#or in other syntax
f(2,3,a=1)

then it has an ambiguity to whether to consider a=1 or a=2 since 2 is the first positional argument and a=1 is an explicit keyword argument .