python poplib get headers from emails

Question

this is my actula code :

import poplib, sys, re, threading, time, Queue
from email import parser

    Mailbox = poplib.POP3(pop3, '110')
    Mailbox.user(username)
    Mailbox.pass_(password)
    numMessages = len(Mailbox.list()[1])
    for i in range(numMessages):
            fullemail = ''
            fullemail = '\n'.join([msg for msg in Mailbox.retr(i+1)[1]])
            msg = parser.Parser().parsestr(fullemail)
            for part in msg.walk():
                    print part.get_payload(decode=True)

print part.get_payload(decode=True) print body of email, how i can print header of email ?

Answer 1

the method items() of email.message.Message/email.message.EmailMessage object may be useful:

for t in msg.items():
    print(t)

t is a tuple like this (key,value).