In the picture below I have the link of the image as src.
but when using BeautifulSoup I got this output:
image['src']
assets/images/content/TUL_5890.jpg
Could you please let me know how to extract the image link in such a case?
I think that is because of the onerror in the code. but I don't know how to fix it .

If you see response html present in
soup,it does not have the entire path as you see in chrome which is probably added by your browser. Hence you were not getting the full path. You will have to extract the tag src and concat it with the FQDN.
This gives us :
EDIT :
As discussed with OP, she needs a solution that directly returns her the full url. Selenium can be used in this case.
Please try the following code.
which gives us the expected output :