Python retrieve DayOfWeek as integer

Question

I need to get the day of the week as integer.

If i use the following for day of the month mydate.day i would like to do the same for weekday.

i tried mydate.weekday but this does not give me the integer (0 for sunday to 6 for saturday).

Any suggestions?

Answer 1

If you are using datetime.datetime, use datetime.datetime.weekday method:

>>> d = datetime.datetime.now()
>>> d
datetime.datetime(2014, 11, 24, 22, 47, 3, 80000)
>>> d.weekday()  # Monday
0
>>> (d.weekday() + 1) % 7
1

You need to (... + 1) % 7 because the method return 0 for Monday, 6 for Sunday.

UPDATE

You can also use datetime.datetime.isoweekday which return 1 for Monday, 7 for Sunday.

>>> d.isoweekday() % 7
1

Answer 2

Python uses 0 for Monday. See the weekday documentation.

import datetime

now = datetime.datetime(2014, 11, 23)
print now
print now.weekday()

This is a Sunday, so prints this:

2014-11-23 00:00:00
6

This is an example of a Monday:

import datetime

now = datetime.datetime.now()
print now
print now.weekday()

This is a Monday so prints this:

2014-11-24 07:47:19.827000
0

Answer 3

I'm a little confused by your wording:

(0 for sunday to 6 for monday) # how would Monday be 6?

But I wonder if you want the isoweekday:

>>> from datetime import datetime
>>> d = datetime.now()
>>> d.isoweekday()
1                                 # Monday

Edit:

In light of your desire for Sunday to be 0, you should go with falsetru's answer (after the edit):

>>> d.isoweekday() % 7

Or simply convert Sunday to 0 elsewhere in your code.