I have the following nested for loop:
int n = 8;
int counter = 0;
for (int i = 0; i < n; i++)
{
for (int j = i + 1; j < n; j++)
{
printf("(%d, %d)\n", i, j);
counter++;
}
}
Which prints (0,1) to (6,7) as expected and the printf() statement is ran 28 times as indicated by counter.
I have been the set the task of improving the efficiency of this code by improving its locality (this is test code, the value of n in the actual program is much larger and i and j are used to index into two 1d arrays) and have employed what I believe to be a fairly standard technique:
int chunk = 4;
for(int i = 0; i < n; i+=chunk)
for(int j = 0; j < n; j+=chunk)
for (int i_chunk = 0; i_chunk < chunk; i_chunk++)
for (int j_chunk = i_chunk + 1; j_chunk < chunk; j_chunk++)
{
printf("(%d, %d)\n", i+i_chunk, j+j_chunk);
counter++;
}
However, here printf() is only being ran 24 times because the j_chunk = i_chunk + 1 means that where before the j loop printed (0,1) to (0,7), the two iterations of the j_chunk loop where i+i_chunk == 0 print (0,1) to (0,3) and (0,5) to (0,7) missing (0,4).
I understand why it is doing this but I can't for the life of me come up with a solution; any help would be appreciated.
First you need to make sure that
jis never in a lower chunk thani, so your outer loops should be:Then you need different behaviour based on whether
iandjare in the same chunk or not. If they are,j_chunkneeds to allways be larger thani_chunk, otherwise you need to go through all possible combinations: