Created a new HTTPS connection and executed a GET method call on the connection URL.
Instead of sending a 301 (30X) redirect I received a response with XHTML page data which inturn when handled in a browser will get submitted automatically and sent to the redirected page, but how to handle the same in java code?
Here is the response data
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<body onload="document.forms[0].submit()">
<noscript><p><strong>Note:</strong> Since your browser does not support JavaScript, you must press the Continue button once to proceed.</p></noscript>
<form action="https://localhost:8083/Login" method="POST">
<div>
<input type="hidden" name="RelayState" value=""/>
<input type="hidden" name="ResponseData" value=""/>
</div>
<noscript>
<div>
<input type="submit" value="Continue"/>
</div>
</noscript>
</form>
</body>
</html>
FYI: I just need to send a HTTP/HTTPS request to the URL in the form action attribute. I'm not planning to open the html in a browser.
Could you provide your connection code? As a generic approach,you can set the setInstanceFollowRedirect(false) for the HttpUrlConnection, so that the redirects don't go through and you can handle them manually. Here is a good example: http://www.mkyong.com/java/java-httpurlconnection-follow-redirect-example/