Regex to get value that comes after certain word

Question

I have a string that will always be dynamic, each time it returns one of the values below:

Return 1 -> Após o vencimento cobrar juros mora/dia de: R$ 3.44 ao dia Multa de: R$ 17,21 Valores expressos em Real (R$\f REMESSA CIP 263

Return 2 -> Após o vencimento cobrar juros mora/dia de: R$ 23.56 ao dia Multa de: R$ 117,80 Valores expressos em Real (R$\f REMESSA **PARCELA 01 / 02**

I need to get the value that comes after '(R$\f', that is, I need a regular expression that returns me:

REMESSA CIP 263` and REMESSA **PARCELA 01 / 02

My regular expression is this -> /\(R\$\\f (.*?)/i but it is not working properly. How can I solve this?

Answer 1

Double escape $ & \f and make the rest of line greedy like:

$arr = Array('Após o vencimento cobrar juros mora/dia de: R$ 3.44 ao dia Multa de: R$ 17,21 Valores expressos em Real (R$\f REMESSA CIP 263',
'Após o vencimento cobrar juros mora/dia de: R$ 23.56 ao dia Multa de: R$ 117,80 Valores expressos em Real (R$\f REMESSA **PARCELA 01 / 02** ');
foreach($arr as $str) {
    preg_match("/\(R\\$\\\\f (.*)/i", $str, $m);
    print_r($m);
}

Output:

Array
(
    [0] => (R$\f REMESSA CIP 263
    [1] =>  REMESSA CIP 263
)
Array
(
    [0] => (R$\f REMESSA **PARCELA 01 / 02** 
    [1] =>  REMESSA **PARCELA 01 / 02** 
)

Answer 2

1. Use a lookbehind assertion to prevent capturing (R$\f.
2. Make .*? greedy so it will actually match something.

result:

(?<=\(R\$\\f ).*