Remove punctation from every value in Python dictionary

Question

I have a long dictionary which looks like this:

name = 'Barack.'
name_last = 'Obama!'
street_name = "President Streeet?"

list_of_slot_names = {'name':name, 'name_last':name_last, 'street_name':street_name}

I want to remove the punctation for every slot (name, name_last,...).

I could do it this way:

name = name.translate(str.maketrans('', '', string.punctuation))
name_last = name_last.translate(str.maketrans('', '', string.punctuation))
street_name = street_name.translate(str.maketrans('', '', string.punctuation))

Do you know a shorter (more compact) way to write this?

Result:

>>> print(name, name_last, street_name)
>>> Barack Obama President Streeet

Answer 1

name = 'Barack.'
name_last = 'Obama!'
empty_slot = None
street_name = "President Streeet?"

print([str_.strip('.?!') for str_ in (name, name_last, empty_slot, street_name) if str_ is not None])

-> Barack Obama President Streeet

Unless you also want to remove them from the middle. Then do this

import re

name = 'Barack.'
name_last = 'Obama!'
empty_slot = None
street_name = "President Streeet?"

print([re.sub('[.?!]+',"",str_) for str_ in (name, name_last, empty_slot, street_name) if str_ is not None])

Answer 2

Use a loop / dictionary comprehension

{k: v.translate(str.maketrans('', '', string.punctuation)) for k, v in list_of_slot_names.items()}

You can either assign this back to list_of_slot_names if you want to overwrite existing values or assign to a new variable

You can also then print via

print(*list_of_slot_names.values())

Answer 3

import re, string

s = 'hell:o? wor!d.'

clean = re.sub(rf"[{string.punctuation}]", "", s)

print(clean)

output

hello world