Is it possible to get a bdd for (x0 ∧ x1 ) ∨ (x0 ∧!x1 ) ∨ (!x0 ∧ x1 ) ∨ (!x 0 ∧!x 1 ) that still has nodes representing the variables x0 and x1, using CUDD? I know the above boolean formula simplifies to the constant function 1. But I still want a BDD that doesnt simplify the formula but represents it as a BDD 'containing' nodes corresponding to both x0 and x1. If not in CUDD, is it possible to do so using some other tool?
Representing BDDs in CUDD without simplification
444 Views Asked by Ashwin Bhaskar At
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David Speck
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You might want to try the MEDDLY Library. (https://meddly.sourceforge.io/).
It is possible to use different types of reduction within this library. For example, quasi-reduction never skips a level (variable). That sounds like what you want.
Hope, that helps.
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Well, this may not be the useful answer but if you use ZDDs (also called 0-sup-BDDs) and you represent constant 1, you will get a graph with all variables - different reduction rule is used. I have generated it by some other tool but CUDD also supports ZDDs.