Send message to localhost using XMPP in python

Question

I have created a program to send chat messages via socket between two ports in localhost. I need a third client who uses xmpp protocol to connect to localhost and sent message to here.When i run my server in terminal it shows this third client as connected

My code is given below:

import xmpp
msg='how r u :)'

client = xmpp.Client('localhost')
print "clienttttttttttttttttttt",client
con=client.connect(server=('localhost',5000))
#client.auth(username, passwd, 'botty')
#client.sendInitPresence()
message = xmpp.Message('localhost', msg)
print "messageeeeeeeeeeeeeeeeeeee",message
message.setAttr('type', 'chat')
client.send(message)

when i execute this code this error occurs

Registering protocol "error" as <class 'xmpp.protocol.Protocol'>(http://etherx.jabber.org/streams)
DEBUG: socket       sent  <?xml version='1.0'?>
  <stream:stream xmlns="jabber:client" to="localhost" version="1.0" xmlns:stream="http://etherx.jabber.org/streams" >

Am using python xmpppy library.What is the issue here.How will i send my message to localhost which uses socket to send messages.Please help????