Set logical status of CheckBox in matplotlib without triggering callbacks?

Question

Is there a way to set the logical status of CheckButtons in matplotlib withput triggering onclick() callbacks?

Here is my scenario:

I am displaying a graph with a large number of traces (50+) and want to give the user the option of displaying a subset of these on the basis of some fixed queries, which the user selects via CheckButton. Every time a button is clicked the the script gets the status of all present CheckButtons via get_status(), computes the indices of the traces that meet the selected criteria, and updates the display accordingly.

In order to make life easier for the user I want to also have a "Select all" and "Clear all" buttons. The best way I can come up with to implement these is to force the logical state of all CheckButtons to True or False without triggering an on_click() callback, then set the visibility of the traces accordingly.

However, CheckButton() does not have a set_status() method https://matplotlib.org/api/widgets_api.html#matplotlib.widgets.CheckButtons

There is a set_active() method but according the documetnation it triggers a callback if eventson is true.

Can someone give me a couple of pointers how to go about doing this? Do I need to set eventson=False for the wdget, then set_active()=True followed by eventson=True? Seems rather clunky, but I can't figure a more elegant way, even after spending way too many hours.

Thanks!

Answer 1

I knew it, as soon as I post a question I figure out the answer. Here is what I came up with for anyone else that wants to do something like this

    check.eventson = False
    status = check.get_status()
    for i,stat in enumerate(status):
        if ((enable and not stat) or (not enable and stat)): 
            check.set_active(i)
    check.eventson = True

here check is a reference to the CheckBox() object and enable is a variable set to True if you want to enable all checkboxes, or False otherwise.