Simplication using Algebraic modification

Question

Studying for exam and came thru this question: Simplify using Algebraic modification put result in sum-of-product form with minimum # of literals

F(A,B,C,D)=(C'+AC'(BD+BD'))D+(BC'+(B+C)'+D')'+C(D+AB'(A'+D'))

I have expended it to this:

C'D+ABC'D+ABC'DD'+B'BD+B'CD+BCD+CD+AA'B'D+AB'CD

my final answer is: AD+AC+CD I'm trying to see if someone else have another thought on this.

Answer 1

I figure it out the answer after thoughtful calculation:

=(C'+AC'B)D+(BC'+B'C'+D')'+C(D+AB'D)
=C'D+ABC'D+(C'+D')'+C(D)
=C'D(1+AB)+CD+CD
=C'D+CD
= D