Store program.exe has stopped working, How can I resolve it?

Question

I'm trying to compile the following code. When I give input to the program then after pressing enter a popup appears which shows that

store program.exe has stopped working

Note: I am using Windows 8.1

Note: I am working on a program (which used in super stores), which includes the following things:

• Product code
• Product name
• Product price
• Total bill calculations

It's just the starting.

#include <stdio.h>
int main (void)
{
  int d, code;
  char product[100], price[100];    
  printf("\t\t Welcome to the Metro Store\n\n\n\n Enter your product code: ");
  scanf("%d",code);

  if(code<100)
    printf("Pharmacy\n Name of the Medicine");

  fflush(stdout);

  fgets(product, 100, stdin);
  printf(product);  
  return 0;
}

Answer 1

For starters you should try

scanf("%d", &code);

You have to tell scanf where to write to. If you don't specify the ampersand (&), scanf will not know where is should write to.

You should read the docs and definitely a good introduction to pointers. If you don't understand pointers, programming in C and C++ is pointless ;-)

Then you can change your fgets() to scanf( "%s", product );

In this case scanf does not need the & because product is short for &product[0]. This can get rather confusing, so get to grips with pointers before continuing.

Answer 2

• First, scanf() expects a pointer type variable as as an argument to the format specifier. Use

  scanf("%d", &code);
              ^^
  

• Second, do not mix up scanf() and fgets(). Otherwise, the fgets() will end up only consuming the newline left by scanf("%d"..). Try to use fgets() for taking user input to be on safer side. However, if you have to use both, use something like

   scanf("%d", &code);
   int ch; while ((ch = getchar())!= EOF && ch != '\n');
   fgets(product,100,stdin);
  

  to avoid the issue with the leftover newline.