This is an api:=>
http://www.google.com/ig/api?weather=[city name]
When i manually put [city name] like http://www.google.com/ig/api?weather=dhakaThen,It's works perfectly.Is there any way to take user input for city name.
<?
$xml = simplexml_load_file('http://www.google.com/ig/api?weather=dhaka'); //Manually,I put 'dhaka' here
$information = $xml->xpath("/xml_api_reply/weather/forecast_information");
$current = $xml->xpath("/xml_api_reply/weather/current_conditions");
$forecast_list = $xml->xpath("/xml_api_reply/weather/forecast_conditions");
?>
<html>
<head>
<title>Google Weather API</title>
</head>
<body>
<h1><?= print $information[0]->city['data']; ?></h1>
<h2>Today's weather</h2>
<div class="weather">
<img src="<?= 'http://www.google.com' . $current[0]->icon['data']?>" alt="weather"?>
<span class="condition">
<?= $current[0]->temp_f['data'] ?>° F,
<?= $current[0]->condition['data'] ?>
</span>
</div>
<h2>Forecast</h2>
<? foreach ($forecast_list as $forecast) : ?>
<div class="weather">
<img src="<?= 'http://www.google.com' . $forecast->icon['data']?>" alt="weather"?>
<div><?= $forecast->day_of_week['data']; ?></div>
<span class="condition">
<?= $forecast->low['data'] ?>° F - <?= $forecast->high['data'] ?>° F,
<?= $forecast->condition['data'] ?>
</span>
</div>
<? endforeach ?>
</body>
</html>
Thanks in advance.
You could create a form
and change
$xml = simplexml_load_file('http://www.google.com/ig/api?weather=dhaka');to$xml = simplexml_load_file('http://www.google.com/ig/api?weather='.$_POST['cityName']);