Task.Factory.StartNew with async lambda and Task.WaitAll

Question

I'm trying to use Task.WaitAll on a list of tasks. The thing is the tasks are an async lambda which breaks Tasks.WaitAll as it never waits.

Here is an example code block:

List<Task> tasks = new List<Task>();
tasks.Add(Task.Factory.StartNew(async () =>
{
    using (dbContext = new DatabaseContext())
    {
        var records = await dbContext.Where(r => r.Id = 100).ToListAsync();
        //do long cpu process here...
    }
}
Task.WaitAll(tasks);
//do more stuff here  

This doesn't wait because of the async lambda. So how am I supposed to await I/O operations in my lambda?

Answer 1

Task.Factory.StartNew doesn't recognise async delegates as there is no overload that accepts a function returning a Task.

This plus other reasons (see StartNew is dangerous) is why you should be using Task.Run here:

tasks.Add(Task.Run(async () => ...

Answer 2

This doesn't wait because of the async lambda. So how am I supposed to await I/O operations in my lambda?

The reason Task.WaitAll doesn't wait for the completion of the IO work presented by your async lambda is because Task.Factory.StartNew actually returns a Task<Task>. Since your list is a List<Task> (and Task<T> derives from Task), you wait on the outer task started by StartNew, while ignoring the inner one created by the async lambda. This is why they say Task.Factory.StartNew is dangerous with respect to async.

How could you fix this? You could explicitly call Task<Task>.Unwrap() in order to get the inner task:

List<Task> tasks = new List<Task>();
tasks.Add(Task.Factory.StartNew(async () =>
{
    using (dbContext = new DatabaseContext())
    {
        var records = await dbContext.Where(r => r.Id = 100).ToListAsync();
        //do long cpu process here...
    }
}).Unwrap());

Or like others said, you could call Task.Run instead:

tasks.Add(Task.Run(async () => /* lambda */);

Also, since you want to be doing things right, you'll want to use Task.WhenAll, why is asynchronously waitable, instead of Task.WaitAll which synchronously blocks:

await Task.WhenAll(tasks);

Answer 3

you have to use the Task.ContinueWith method. Like this

List<Task> tasks = new List<Task>();
tasks.Add(Task.Factory.StartNew(() =>
{
    using (dbContext = new DatabaseContext())
    {
        return dbContext.Where(r => r.Id = 100).ToListAsync().ContinueWith(t =>
            {
                var records = t.Result;
                // do long cpu process here...
            });
        }
    }
}

Answer 4

You can do like this.

    void Something()
    {
        List<Task> tasks = new List<Task>();
        tasks.Add(ReadAsync());
        Task.WaitAll(tasks.ToArray());
    }

    async Task ReadAsync() {
        using (dbContext = new DatabaseContext())
        {
            var records = await dbContext.Where(r => r.Id = 100).ToListAsync();
            //do long cpu process here...
        }
    }