So I have this piece of Pascal code:
program P;
var a: array [1..2] of Integer;
var i :Integer;
var k :Integer;
procedure update(x,y,z: Integer);
begin
x := x+1;
y := x*2;
x := y;
k := x;
end
begin
a[1] := 5; a[2] := 10;
k := 3;
for i:=1 to 2 do
begin
update(a[i],a[2],k);
print(a);
print(k)
end
end.
(assume that 'print' prints elements of array separated by spaces, and then prints a new line and also for an integer it just prints it)
And i'm trying to understand how different the output would be if the function call was by value-result or by reference.
obviously, if it was just by-value, it's easy to tell that the procedure wouldn't make any difference to the actual parameter, i.e the output (in by value) should be: 5 10 3 5 10 3.
I think that if it was be value-result it would have been, at least the first iteration: 12 12 12. at the case of by reference I got confused. What would it be?
You haven't declared any variable parameters. The variable
K
will be changed, but that doesn't count in this context and is generally considered bad practice.The output of this program should be
10 15
.With declaring
Z
as constant parameter you promise to the compiler that you don't change that value. The following procedure variant should give an error while compiling.