int x = ~!printf;
printf("%d\t%x",x,x);
It gives : -1 ffff
Can anyone explain ?
What does this code mean in C, " int x = ~!printf; "?
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printfwithout arguments is the function pointer, worth a non-zero value (it's built-in so the pointer cannot be zero)Now you apply logical negation (
!) on this non-zero value: you get zero.Now negate this zero bit-wise (using bit to bit negation
~), you get all 1s in theintbit range (which can vary depending on the compiler)Printing it in decimal yields
-1, and in hexadecimal yields a given number offs, depending on the size of the integer (on my 32bit integer compiler, I getffffffff)(note that -specially the negation of the function pointer- cannot be part of some valid program, this is only for academic purposes)