How is the "X% slower" number computed? I thought maybe it was:
(fastest - slower) / fastest
but in this case, that's:
(672555 - 194412) / 672555 = 0.7109351651537792
Maybe the margin of error is used as well?
What's the relationship between ops/second and percentage slower in JSPerf?
77 Views Asked by Nick Heiner At
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There are 1 best solutions below
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See https://github.com/bestiejs/benchmark.js/blob/7fc4c3cf7c4bccff4dbce58883a4181c2e830f85/example/jsperf/ui.js#L556: