What the meaning of "0x48151642" in malloc_debug_leak.cpp

Question

Recently, I'm reading the libc-init code of android. When I read the code in malloc_debug_leak.cpp, line 70 and line 263, it said as follows.

#define GUARD               0x48151642 
static uint32_t MEMALIGN_GUARD      = 0xA1A41520;

I know the GUARD and MEMALIGN_GUARD meaning, but I really don't get the meaning of the value, for example static uint32_t MEMALIGN_GUARD = 0x0001 is OK？or any other value. Does 0xA1A41520 have some useful info？

https://i.stack.imgur.com/9lgzv.png

https://i.stack.imgur.com/ZMM5u.png

Answer 1

I really don't get the meaning of the value

It's a magic value, intended to catch common programming mistakes. See this wikipedia article for detailed explanation.

Would 0x0001 be OK?

No. It lacks the "distinctive unique value that is unlikely to be mistaken for other meanings" property.

When you see value 0x1 in a certain location memory, such value could very likely be placed there by lots of different code sequences. On the other hand, when you see 0xA1A41520, it is quite unlikely (though still possible) that that value was placed there by code other than the one that is using MEMALIGN_GUARD.