I don't understand why I can't decompose a (let's say IO) monad. Like IO a -> a?
My question originated when using happstack and wanting to get the Text out of ServerPart (Maybe Text) which is returned by (optional $ lookText "domain").
Then I remembered reading that IO monad can't be escaped.
I've read about unsafePerformIO and the reasons why it is bad, but none of those reasons seem to answer my question.
Can
Monads be escaped from?Yes. This is very easy with many
Monads, such asMaybe,Either a,State s,Identity, and more. One of the most commonMonads that is escaped from is the functionMonad:(->) r. If it weren't possible to turn a function into a value, then Haskell wouldn't have much going for it.Can
IObe escaped from?Unfortunately, yes. It would be a lot better for beginners if they didn't google around and see that they can technically escape from
IOusingunsafePerformIO, which as you might have guessed is not safe. It is not meant to be used in normal code, but is rather a backdoor into the runtime system for when you really need it. Primarily, it's used for implementing some lower level libraries likeVector, but also for interfacing with external shared libraries (DLLs). If you're not writing that kind of code, don't useunsafePerformIO. Otherwise, you will end up with code that becomes difficult to reason about and maintain because it bypasses the type system.How do we escape from other
Monads?It varies from
MonadtoMonad, but most monad transformers haverun-,eval-orexec-methods:The
MaybeMonadhas several ways to escape from it:So as you can see, not all of them are safe to use either.
What does this have to do with Happstack?
I don't know, I haven't used Happstack enough to know about it. However, a quick search led me to this example on their website, which looks pretty applicable to your situation.