I put this into java and I was given the result 2. Was wondering why it isn't an ArithmeticException, as shouldn't (int)(2/0.9) turn into 2/0. All help is appreciated.
Why does (int)(2/0.9) = 2?
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Your code is
So the
int
-cast is only applied to the result after computing2 / 0.9
. Now2 / 0.9
divides anint
by adouble
value. In such a case theint
will also be interpreted asdouble
(2.0
in this case). The result is thus likeThis process is known as numeric promotion (it uses widening primitive conversion here JLS§5.1.2). From JLS§5.6:
After that you cast to
int
which will round the value to the next lower integer,2
in this case. Thus the result is2
.What you expected would be the result of an expression like
which first casts the
0.9
to anint
before dividing. In this case you would correctly getyielding the expected
ArithmeticException
.