Good morning
I have a TabbedPage in my application. Due to restictions I would like to display one more tab on Android than on iOS.
My current TabbedPage look like:
<TabbedPage>
...
<ContentPage x:Name="Page1"/>
<ContentPage x:Name="Page2"/>
<ContentPage x:Name="Page3"/>
<ContentPage x:Name="Page4"/>
</TabbedPage>
I have decided to render Page3 only for Android. I changed my code into:
<TabbedPage>
...
<ContentPage x:Name="Page1"/>
<ContentPage x:Name="Page2"/>
<OnPlatform x:TypeArguments="Page">
<On Platform="Android">
<On.Value>
<ContentPage x:Name="Page3"/>
</On.Value>
</On>
</OnPlatform>
<ContentPage x:Name="Page4"/>
</TabbedPage>
This leads to runtime exception when entering into this TabbedPage:
An error occurred: 'Value cannot be null. Parameter name: item'. Callstack: ' at Xamarin.Forms.ObservableWrapper`2[TTrack,TRestrict].Add (TRestrict item) [0x00008] in D:\a\1\s\Xamarin.Forms.Core\ObservableWrapper.cs:27
I tried to remove x:Name but did not work. Any ideas?
PS. As a workaround I am always able to:
Constructor()
{
if(Runtime.IsIOS)
{
this.Children.Remove(this.Page3)
}
}
However would be better to not render it at all and have it at XAML level.
Unless someone comes up with a way to do this in XAML, this is the best you can do (building on Jason's comment):
xaml:
c#:
This has the advantage of not constructing the page at all on iOS.
It also makes it easy to test whether page3 is there (
page3 != null).In practice, the other pages will typically be their own classes. Given
partial class Page3 : ContentPageelsewhere: