I have been trying to shift my number with the formula m*2^-n by using Logical Shift Right (LSR). for m = 8 and n=-2 I should be getting 8(2)^-2 ie; 2, but I get 0 for some unknown reason.
ARM7 assembly shifting a number with a signed integer
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You need to first negate
R1before you can doASR. Shift values are unsigned, a negative shift value is interpreted as a very large positive shift, leading to a result of zero.