class A { ... };
A& getA();
A anA = getA();
What happens exactly on line 3 ?
Is the copy constructor of A called, thus creating an object independent from the one returned (by reference) by the function?
Assign a reference return value to a non-reference variable
5.3k Views Asked by Sébastien At
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Yes. The copy constructor takes a reference to the source object as it's parameter and a copy is independent of the original object assuming the copy constructor does a deep copy.