I'm studying right now, at my university, DFA and NFA automatons and how to implement some of them using Java code.
I am having some trouble with this exercise: we have 4 different laboratory turns (T1, T2, T3 and T4) and we need to write code in order to recognize if a particular string (composed of the university badge number of a student and his name, e.g., 123321Johnson
) corresponds to T2 or T3.
We know that:
- T1 is the turn of the ones who have an odd badge number and surname between "A" and "K"
- T2 is the turn of even badge numbers and surnames between "A" and "K"
- T3 is the turn of odd badge numbers and surnames between "L" and "Z"
- T4 is the turn of even badge numbers and surnames between "L" and "Z"
We also know that the string has to be composed of at least one number and at least one letter.
E.g., the automaton has to accept "1232324Gac"
or "1232323Lum"
but not "121234Lum"
or "121233Gac"
.
Here's the code I wrote:
import java.util.Scanner;
public class Es3 {
static Scanner sc = new Scanner(System.in);
String s = sc.next();
public static boolean scan(String s)
{
int state = 0;
int i = 0;
while (state >= 0 && i < s.length()) {
final char ch = s.charAt(i++);
switch (state) {
case 0:
if (ch >= 0 && ch <= 9)
state = 1;
else
state = -1;
break;
case 1:
if (ch >=0 && ch <=9)
state = 1;
else if (ch >='a' && ch <='k')
if ((s.charAt(i--))%2==0)
state = 2;
else
state = -1;
else if (ch >='l' && ch <='z')
if ((s.charAt(i--))%2==1)
state = 3;
else
state = -1;
else
state = -1;
break;
case 2:
if (ch >='a' && ch <='z')
state = 2;
else
state = -1;
break;
case 3:
if (ch >='a' && ch <='z')
state = 3;
else
state = -1;
break;
}
}
return (state == 2 || state == 3);
}
public static void main(String[] args)
{
System.out.println(scan(args[0]) ? "OK" : "NO");
}
}
Obviously, the code is not working, but this is important to show the general purpose of the exercise.
Could someone help me?
The reason your algorithm wasn't working is because you were trying to compare
char
values toint
values, which wouldn't give the anticipated result. Also, when you were checking if achar
value was in a certain letter range, you didn't take capital letters into account.I think the code above should do what you’re trying to do.