C++ Passing by pointer and passing by reference

Question

#include<iostream>

using namespace std;

class A{
        int *numbers[5];
        public:
            void assignment(int ** x){
                    for(int i=0;i<5;i++)
                            numbers[i]=x[i]; //not changing just the value of *numbers[i] but the pointer numbers[i]
            }
            void print(){
                    for(int i=0; i<5;i++)
                            cout<< *numbers[i]<<endl;
            }
};

int main(){
    int *x[5];
    for(int i; i<5;i++){
            x[i]= new int(i);
            cout<<*x[i]<<endl;
    }
    cout<<endl;
    A numbers;
    numbers.assignment(x);
    numbers.print();
    return 0;
}

My question is very specific. I want to do the same thing as the code above but instead of passing the argument of function assignment(int **) by pointer to do it by reference. How can I achieve that?

Answer 1

Use:

void assignment(int* (&x)[5]) ...

edit: for the comment "if the length... wasn't standard...", you can use a template:

template<int N> void assignment(int* (&x)[N]) ...

The compiler will automatically deduce N.