Changing from dynamic memory to static memory

Question

I'm trying to change a dynamic memory object to static memory use to hopefully free up memory in a way.

Original code(dynamic):

Class.h:

Class() {
  auto output = std::unique_ptr<uint8_t[]>(new uint8_t[size]);

  Call(output.get());
  memcpy(randomlocation, output.get(), size);
}

Call(Byte *dest) {
  doStuff..
}

I'm very confused how I can do a similar .get() but with a non unique-ptr. I've seen &* may work but haven't had any luck.

My trial of static:

Class.h:

uint8_t *output[64];

Class() {
  Call(reinterpret_cast<Byte*>(&*output));
}

I have tried other ways like no &* and different ways of casts and haven't had any luck. It compiles sometimes, but doesn't seem to work right. Wanting to see if this part is wrong, if not then I will at least know I'm doing this part right.

Answer 1

Use uint8_t output[64]; instead. The output is like uint8_t* to 64 bytes of static memory.

This works:

void cal(uint8_t* dest)
{
    ...
}

uint8_t output[64];    
cal(output);