I came across this particular color-transfer tutorial using OpenCV:
https://www.pyimagesearch.com/2014/06/30/super-fast-color-transfer-images/
and implemented it like this:
def color_transfer(source, target):
# compute color statistics for the source and target images
source = cv2.cvtColor(source, cv2.COLOR_BGR2LAB).astype("float32")
target = cv2.cvtColor(target, cv2.COLOR_BGR2LAB).astype("float32")
# compute color stats for both images
(lMeanSrc, lStdSrc, aMeanSrc, aStdSrc, bMeanSrc, bStdSrc) = self.image_stats(source)
(lMeanTar, lStdTar, aMeanTar, aStdTar, bMeanTar, bStdTar) = self.image_stats(target)
# split the color space
(l, a, b) = cv2.split(target)
# substract the means from target image
l -= lMeanTar
a -= aMeanTar
b -= bMeanTar
# check values
print(lStdSrc, aStdSrc, bStdSrc)
print(lStdTar, aStdTar, bStdTar)
print(lMeanSrc, aStdSrc, bMeanSrc)
# process lab computation
l = (lStdSrc / lStdTar) * l
a = (aStdSrc / aStdTar) * a
b = (bStdSrc / bStdTar) * b
# add the source mean
l += lMeanSrc
a += aMeanSrc
b += bMeanSrc
# clipping the pixels between 0 and 255
l = np.clip(l, 0, 255)
a = np.clip(a, 0, 255)
b = np.clip(b, 0, 255)
# merge the channels
transfer = cv2.merge([l, a, b])
# converting back to BGR
transfer = cv2.cvtColor(transfer.astype("uint8"), cv2.COLOR_LAB2BGR)
return transfer
In this particular code:
# process lab computation
l = (lStdSrc / lStdTar) * l
a = (aStdSrc / aStdTar) * a
b = (bStdSrc / bStdTar) * b
it gets the standard deviation of the source, so when we combine the source and the target image, it will become a plain image as well since the lab will all be 0.
How can I fix this? It works when the source image is not a plain image with color.