correct my Python leap year code as per below conditions

Question

• The year can be evenly divided by 4, is a leap year, unless:
• The year can be evenly divided by 100, it is NOT a leap year, unless:
• The year is also evenly divisible by 400. Then it is a leap year.

Please correct my code. I'm not looking for alternatives. please use the above conditions

def is_leap(year):
    nonleap = False
    leap = True
    x = year % 4
    y = year % 100
    z = year % 400
    if(x == 0):
        if((y % 2 != 0) or ((y % 2 == 0) and (z % 2 == 0))):
            return leap
    else:
        return nonleap

year = int(input())
print(is_leap(year))

Answer 1

def is_leap(year):
    x = year % 4
    y = year % 100
    z = year % 400
    if(x == 0):
        if((y != 0) or ((y == 0) and (z == 0))):
            return True
        else:
            return False
    else:
        return False

year = int(input())
print(is_leap(year))

Answer 2

The problem with your code is that you're checking whether y and z are divisible by 2.

The solution using your code as base could look like this

def is_leap(year):
    nonleap = False
    leap = True
    x = year % 4
    y = year % 100
    z = year % 400
    if x == 0:
        if (y == 0) and not (z == 0):
            return nonleap
        else:
            return leap
    else:
        return nonleap

But here's a more elegant pythonic solution https://www.hackerrank.com/challenges/write-a-function/forum

def is_leap(year):
    return year % 4 == 0 and (year % 400 == 0 or year % 100 != 0)