Below is my build configuration file: build.js
{
appDir: '../src',
baseUrl: 'libs',
paths: {
app: 'js'
},
dir: '../prod',
out:"../js/main-built.js",
fileExclusionRegExp: /.less$/,
optimize: "uglify2",
optimizeCss: "standard",
modules: [{
name: '../js/main'
}]
}
I am using "grunt-requirejs": "~0.4.2" as my build npm and Gruntfile requirejs configuration + r.js 2.1.16:
requirejs: {
std: {
options: grunt.file.read('config/build.js')
}
}
Whenever i am try to execute grunt requirejs it is throwing below error on my console:
Error: Error: Missing either an "out" or "dir" config value. If using "appDir" for a full project optimization, use "dir". If you want to optimize to one file, use "out".
at Function.build.createConfig (d:\app\node_modules\grunt-requirejs\node_modules\requirejs\bin\r.js:27717:19)
I want to consolidate some of the JS files like jquery and its plugins etc. into 1 file and i am using AMD pattern similar to project https://github.com/hegdeashwin/Protocore
Can you please help me out here and tell what i have missed in my configuration ?
Thanks & Regards
You're using
grunt.file.read
which reads a file and returns the file's content as a string.Use
grunt.file.readJSON
instead.