getting the return value of Future Function in Flutter without Stateless/Stateful Widget

Question

I just want to return the value of each condition and use it as the value of the function.

Here is my code for it.

var getStuff = chechIfExisting();

chechIfExisting() async {
  var isExisting = await FirebaseFirestore.instance
      .collection('merchants')
      .doc(userUid)
      .get();
  if (isExisting.exists) {
    return 'exists';
  }
  if (!isExisting.exists) {
    return 'nope';
  } else {
    return 'error';
  }
}

and I am not using any Stateless and Stateful Widget since this file contains only the widgets such as appbar/mydrawer. I wanted to use the 'getStuff' variable in a if statement under the myDrawer Widget, since I want to dynamically check if the the data that I am fetching is existing or not.

myDrawer(BuildContext context) {
print('getStuff');
// only prints 'Instance of 'Future<String>' and does not return the value.
}

I want to be able to use the 'getStuff' variable as

myDrawer(BuildContext context) {
if(getStuff == 'exists'){
 // code here
}

Any helps/ideas on how to solve this are appreciated!

Answer 1

with this line:

var getStuff = chechIfExisting();

You're not waiting for the method to finishes executing, since it's a Future, not using either await/async or then to resolve values after the Future finishes will get you that getStuff() is a type of Instance of 'Future<String>, before the running of the myDrawer function, you need either to:

var getStuff = await chechIfExisting(); // inside an async method

or:

chechIfExisting().then((resolvedValue) {
  getStuff = resolvedValue;
 });

then you can run the myDrawer method and get it working fine