Handling [FileInfo()] format

Question

I'm using scrcpy module and trying to get info about folder in mobile device.

With command devices.sync.list(remote), where remote is serial of phone and devices is Client, I will get FileInfo format type of respond:

[FileInfo(mode=16888, size=3452, mtime=datetime.datetime(2023, 4, 24, 14, 28, 8), path='000_230424_14-26-50')]

How can I handle this output?

I've tried for (mode, size, mtime, path) in devices.sync.list(remote): but getting the TypeError TypeError: cannot unpack non-iterable FileInfo object.

Answer 1

[FileInfo(mode=16888, size=3452, mtime=datetime.datetime(2023, 4, 24, 14, 28, 8), path='000_230424_14-26-50')] simply means that you have received a list containing one FileInfo object.

for fileinfo in devices.sync.list(remote): will iterate over this list, giving you each FileInfo object assigned to the fileinfo variable.

Presumably you can then access its properties as attributes:

for fileinfo in devices.sync.list(remote):
    print(fileinfo.mode)
    print(fileinfo.size)
    # etc.