Question

decltype, recursive type deduction for overloaded operator

score 411 · Answer 1 · 2015-06-14 12:57:59

411

Views

decltype, recursive type deduction for overloaded operator

Published on 14 June 2015 at 12:57

score 677 · Answer 2 · 2015-06-11 15:43:28

677

Views

How can I write a decltype expression using a function that expects a non-const reference?

Published on 11 June 2015 at 15:43

score 756 · Answer 3 · 2015-06-16 14:59:52

756

Views

'const decltype((a))' does not declare a const reference?

Published on 16 June 2015 at 14:59

score 502 · Answer 4 · 2015-06-17 13:42:37

502

Views

Alias the return type of a const overloaded function

Published on 17 June 2015 at 13:42

score 220 · Answer 5 · 2015-06-16 00:09:38

220

Views

"Emulating" std::declval issues. Works (kind of) in g++, fails to compile in clang++

Published on 16 June 2015 at 00:09

score 409 · Answer 6 · 2015-06-20 18:58:01

409

Views

Initialization of a member variable tuple

Published on 20 June 2015 at 18:58

score 406 · Answer 7 · 2015-06-25 03:52:48

406

Views

decltype() of captured variable in lambda: GCC bug and/or Clang bug?

Published on 25 June 2015 at 03:52

score 116 · Answer 8 · 2015-06-26 02:39:17

116

Views

Pass a comparison function for Key Type without using decltype[c++]

Published on 26 June 2015 at 02:39

score 134 · Answer 9 · 2016-12-26 12:55:26

134

Views

VC++ Bug with Decltype and Universal Reference or Undefined Behavior?

Published on 26 December 2016 at 12:55

score 203 · Answer 10 · 2017-01-08 00:29:16

203

Views

A more elegant way for a template function grouping values?

Published on 08 January 2017 at 00:29

score 1.3k · Answer 11 · 2017-01-08 04:23:18

1.3k

Views

Deducing address of template class's overloaded method results in "error: expected primary-expression before ‘decltype’"

Published on 08 January 2017 at 04:23

score 253 · Answer 12 · 2013-12-03 14:24:56

253

Views

decltype to declare parameter of return type of a function (without auto)

Published on 03 December 2013 at 14:24

score 398 · Answer 13 · 2013-12-10 05:05:15

398

Views

C++: Is it okay to use decltype to copy types from my header files?

Published on 10 December 2013 at 05:05

score 214 · Answer 14 · 2013-12-10 16:40:03

214

Views

VS2013 - decltype of class method does not work as default template parameter does not work

Published on 10 December 2013 at 16:40

score 1.2k · Answer 15 · 2017-08-30 16:24:37

1.2k

Views

c++ remove noexcept from decltype returned type

Published on 30 August 2017 at 16:24

score 635 · Answer 16 · 2017-08-31 11:27:34

635

Views

Why decltype() yelds a pointer to reference?

Published on 31 August 2017 at 11:27

score 450 · Answer 17 · 2017-09-03 05:40:01

450

Views

c++11 decltype(e) is the type of the entity named by e

Published on 03 September 2017 at 05:40

score 44 · Answer 18 · 2017-09-16 19:51:09

44

Views

Call a function if the template contains a member variable C++

Published on 16 September 2017 at 19:51

score 434 · Answer 19 · 2011-01-29 16:32:26

434

Views

How is decltype supposed to work with operator,

Published on 29 January 2011 at 16:32

score 18.7k · Answer 20 · 2011-01-31 00:15:03

18.7k

Views

C++11 lambda in decltype

Published on 31 January 2011 at 00:15

List Question

decltype, recursive type deduction for overloaded operator

How can I write a decltype expression using a function that expects a non-const reference?

'const decltype((a))' does not declare a const reference?

Alias the return type of a const overloaded function

"Emulating" std::declval issues. Works (kind of) in g++, fails to compile in clang++

Initialization of a member variable tuple

decltype() of captured variable in lambda: GCC bug and/or Clang bug?

Pass a comparison function for Key Type without using decltype[c++]

VC++ Bug with Decltype and Universal Reference or Undefined Behavior?

A more elegant way for a template function grouping values?

Deducing address of template class's overloaded method results in "error: expected primary-expression before ‘decltype’"

decltype to declare parameter of return type of a function (without auto)

C++: Is it okay to use decltype to copy types from my header files?

VS2013 - decltype of class method does not work as default template parameter does not work

c++ remove noexcept from decltype returned type

Why decltype() yelds a pointer to reference?

c++11 decltype(e) is the type of the entity named by e

Call a function if the template contains a member variable C++

How is decltype supposed to work with operator,

C++11 lambda in decltype

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