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How do I add a class inside the XML root, in an existing XML file?

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306

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List Question

How do I add a class inside the XML root, in an existing XML file?

XmlElement shows up as lowercase in SOAP

XmlSerializer Deserializing Array/List of Multiple Objects at Root

Replace ArrayOf* Root Element using API Controller in Visual Studio C#

How to add a root to an XML file?

One POJO but the different XmlRootElement name

XmlRoot attribute serialization to a file

Rename serializable class

Get attribute names and values from ElementTree

JAXB dynamic XML root class name

xmlconvert string to date

Serializing class decorated with XmlRoot, error when used in List

XmlRoot() for Xml Serilization does not work

How to consume XML with more than one possible root element in Spring REST client

How to print pretty JSON using docx4j into a word document?

JAXB Marshall/unmarshall

PYTHON : How to add root node to an XML

JaxB unmarshall unexpected element error

Serialize XML without tag name

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