When n=2^2k for some k >=0, then recurrence relation T(n)=√n T(n/2) + √n, T(1)=1, if we evaluate this what answer will come? Using Back Substition method.
i tried it but i didn't get proper answer. right answer is √n(logn+1).
Here recurrence relation is given and using back substituion what value i will get?
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