How apply an order to CONSTRUCT in SPARQL

Question

Doing this query SPARQL

select ?s ?p ?o 
WHERE
{

  GRAPH <graph_url> {
    ?s ?p ?o
  }
}
ORDER BY DESC(?s) DESC(lang(?o) = "it") DESC(lang(?o) = "en") ?o

I order each element in the graph_url, such that given two element rdf of the same type I have first the element with attribute value "it" and then the elements with attribute values "en".

However if I apply a CONSTRUCT over it

CONSTRUCT  { ?s ?p ?o }
WHERE
{

  GRAPH <graph_url> {
    ?s ?p ?o
  }
}
ORDER BY DESC(?s) DESC(lang(?o) = "it") DESC(lang(?o) = "en") ?o

I loose this order. I found out that CONSTRUCT doesn't mantain the order given by ORDER BY.

There is a way to construct an rdf with construct such that the graph resulted is ordered?