How to acces exiv2 ImageSize Property?

Question

I create images from blender, and they lack Exif metadata, which I add using the bash command exiv2. (Because the software these images are passed to will use the metadata.)

For example, I can set the Image Width to 960 using exiv2 -M"set Exif.Image.ImageWidth 960" image.jpg and then read it out using exiv2 -g Exif.Image.ImageWidth -Pv image.jpg.

For a quick summary, I can do exiv2 image.jpg to get a list of set Exif metadata. This includes

$ exiv2 image.jpg
File name       : image.jpg
File size       : 32975 Bytes
MIME type       : image/jpeg
Image size      : 960 x 540

How can I use this Image size to set Exif.Image.ImageWidth and Exif.Image.ImageLength in bash?

The standard Exif tags don't list ImageSize.

Answer 1

As ghoti suggested, parsing the output works:

exiv2 image.jpg  | grep  "Image size" | sed -n "s/^.*Image size\s*:\s\([0-9]*\)\sx\s\([0-9]*\).*$/\1/p"

gives the width, and

exiv2 lowerCircle_0100.jpg  | grep  "Image size" | sed -n "s/^.*Image size\s*:\s\([0-9]*\)\sx\s\([0-9]*\).*$/\2/p"

the height.

I'm still hoping for a cleaner answer though.

Explanation of the sed command:

 sed -n "s/^.*Image size\s*:\s\([0-9].*\)\sx\s\([0-9]*\).*$/\1/p"

 -n            suppress printing
 "s/           substitute match
 ^.*           everything from the start
 Image size    until "Image size" is encountered
 \s*:\s        whitespace, colon, a single space
 ([0-9]*\)    any number of digits. store that in \1
 \sx\s         space x space
 ([0-9]*\)    another group of digits. store that in \2
 .*$           everything until the end of line
 /\1           substitute all that with the first group
 /p"           and print the substituted result

Answer 2

or without sed hieroglyphs

exiv2 pr  X.jpg | awk -F: '/Image size/ {print $2}' | cut -dx -f1 | tr -d ' '

and

exiv2 pr  X.jpg | awk -F: '/Image size/ {print $2}' | cut -dx -f2 | tr -d ' '