How to convert Date from 2023-11-10 09:44:00.038860 to 2023-11-10T09:44:20.001+00:00 in spring boot application

Question

I am getting response from ELK and mapping it to an object using ObjectMapper and then return the response as JSON. The ELK response has a Date datatype field with the format yyyy-MM-dd HH:mm:ss.SSSSSS. The ELK response retrieved is in UTC and I want the API JSON response to be in UTC as well. So no timezone conversion required. I want the JSON payload to display the Date field in the format 2023-11-09T03:00:35.563+00:00. It tried to set @JsonFormat on the field but did not work.

@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSSSS")
private Date timestamp;

I tried using multiple formats yyyy-MM-dd'T'HH:mm:ss.SSSX or yyyy-MM-dd'T'HH:mm:ss.SSS'Z'. But throws the same exception.

Also tried the following ,

• to set the date format for the mapper.

SimpleDateFormat out = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSSSS");
mapper.setDateFormat(out);

• to convert using simple Date format.

SimpleDateFormat in = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS");
SimpleDateFormat out = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSSSS");
String dateIn = in.format(Obj.getTimestamp());
Date dateOut = out.parse(dateIn);

Am I using the correct format for 2023-11-09T03:00:35.563+00:00? The exception thrown is Exception thrown [Cannot deserialize value of type java.util.Date from String "2023-11-10 09:44:00.038860": expected format " yyyy-MM-dd'T'HH:mm:ss.SSSSSS" or unparseable date exception is thrown. Thanks!

Answer 1

String manipulation

In your case, the simplest approach is mere string manipulation.

String input = "2023-11-10 09:44:00.038860" ;
String result = 
    input
    .replace( " " , "T" )
    .substring( 0 , 24 )
    .concat( "+00:00" )
;

Answer 2

import com.fasterxml.jackson.annotation.JsonFormat;
import java.util.Date;

public class YourResponseObject {
    private Date yourDateField;

    // Getter method for the Date field
    @JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd HH:mm:ss.SSSSSS")
    public Date getYourDateField() {
        return yourDateField;
    }

    public void setYourDateField(Date yourDateField) {
        this.yourDateField = yourDateField;
    }
}