How to detect onTouch release event in Android after object is set invisible?

Question

Here's what I need.

Let's say we have objects A, B. Initially object B has visibility set to GONE and object A has visibility set to VISIBLE.

Touching object A must make A GONE and B VISIBLE. Releasing B must make B GONE and A VISIBLE. Problem is that it must be done without pressing B again.

Here's what I tried.

1. Set on touch event ACTION_DOWN on A and ACTION_UP on same A, that appears and hides B just like described. This cannot work, because ACTION_UP is not triggered after setting visibility of A to GONE.

2. Set on touch event ACTION_DOWN on A that will make A GONE and make B VISIBLE, at same time new event listener is set such that ACTION_UP on B would inverse visibility of the objects. This doesn't work either since after B appears, I need to release, press B again and then release to make it work.

My questions.

1. Is it possible to to set onTouch listener in such way that object is assumed to be touched? So that there would be no need to press it again?

2. Is it possible to detect onTouch ACTION_UP event after visibility of object is set to GONE?

All ideas, examples, links will be appreciated. Thanks for help!

Answer 1

Try this

  buttonA.setOnTouchListener(new OnTouchListener() {
 @Override
 public boolean onTouch(View v, MotionEvent event) {
    if(event.getAction() == MotionEvent.ACTION_DOWN) {
      YourMethodForButtonBGoesVisible();
      YourMethodForButtonAGoesGone();
    } else if (event.getAction() == MotionEvent.ACTION_UP) {
        YourMethodForButtonAGoesVisible();
        YourMethodForButtonBGoesGone();
    }
    return true;
 }    
});

I don't know if when the button A gone this will detect the MotionEvent.ACTION_UP.