How to extract the userkey value when %2F is present in an expression in jmeter

Question

I am creating a script in JMeter for performance testing!
I need to get the userkey form the response header.
As we can see below is the short response for the same:
&Userkey=AMfN%2Fm1wlh

And I tried using the below regex:
Userkey=(.+?)\n
Userkey=(.+?)%2F(.+?)\n
But didn't got solution using post processor, i.e. regular expression extractor in JMeter

Answer 1

Try the following regular expression:

Userkey=(.*)

Where:

• . - matches any character
• * - repetition
• () - grouping

As you can see it produces a match in "RegExp Tester" mode of the View Results Tree listener:

More information:

• Apache JMeter - Regular Expressions
• Using RegEx (Regular Expression Extractor) with JMeter